# 实验4

assume cs:code
code segment
	mov ax, # 带补充
	mov ds,ax
	mov ax,0020h
	mov es,ax
	mov bx,0
	mov cx, # 待补充
s:  mov al,[bx]
	mov es:[bx],al
	inc bx
	loop s

	mov ax,4c00h
	int 21h
code ends
end